n=1 # Nombre sur lequel porte le calcul exponentiel dichotomique x=1 while v<>1: if v%2==0: v=v/2 n=n+n else: x=x+n n=n+n v=(v-1)/2 print "(",x,",",n-1,",",v,")" print "\na^",x," * a^",n-1," = a^",(x+n)-1,"\n"